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Imagine three circuits.
1. One bulb.
2. Two bulbs in series.
3. Two bulbs in parallel.
The batteries are the same in each circuit. In what order do the batteries run down? (If it matters to you, assume that the batteries all have negligible internal resistance and that the resistance of the bulbs doesn't change with current).
This is the correct order
Circuit 3 (parallel) runs down after, say 1 hr
Circuit 1 (single) runs down after 2 hours
Circuit 2 (series) runs down after 4 hours
The times assume (incorrectly) that the batteries provide a constant voltage before suddenly dropping to zero.
Remember that each of the parallel bulbs are as bright as the single bulb. So the two bulbs in parallel demand energy from the battery twice as quickly as one alone. That’s why the parallel circuit runs down first.
It might be tempting to believe that the series circuit runs down at the same time as the single bulb. This would assume that each series bulb was half as bright as one alone. But in fact each of the series bulbs is a quarter as bright. Brightness depends on how quickly energy is transferred, in other words, power.
Power depends on both current (how quickly charges are arriving) and voltage (how much energy each charge transfers). In the series circuit the current round the circuit is halved and the voltage is shared between two bulbs, so energy is transferred to each bulb only a quarter as quickly as if it were by itself.
In this simulation you can drag a power meter to different parts of a series and parallel circuit to see how the different brightnesses can be explained.